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Solution
Given :Â $$m=9$$ and $$n=\frac{1}{3}m$$
=> $$n=\frac{1}{3}\times9=3$$
To find : $$\sqrt{(m)^{2}-(n)^{2}}$$
= $$\sqrt{(9)^2-(3)^2}$$
= $$\sqrt{81-9}=\sqrt{72}=6\sqrt2$$
=> Ans - (B)
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