As shown in the figure, a network of resistors is connected to a battery of 24 V with an internal resistance of 3 $$\Omega$$. The currents through the resistors $$R_4$$ and $$R_5$$ are $$I_4$$ and $$I_5$$ respectively. The values of $$I_4$$ and $$I_5$$ are:

A

$$I_4 = \frac{8}{5}$$ A and $$I_5 = \frac{2}{5}$$ A

B

$$I_4 = \frac{24}{5}$$ A and $$I_5 = \frac{6}{5}$$ A

C

$$I_4 = \frac{6}{5}$$ A and $$I_5 = \frac{24}{5}$$ A

D

$$I_4 = \frac{2}{5}$$ A and $$I_5 = \frac{8}{5}$$ A