ABCD is a cyclic quadrilateral, AB is the diameter of the circle. If $$\angle$$ACD = 50$$^\circ$$, the measure of $$\angle$$BAD is
Given, Â $$\angle$$ACD = 50$$^\circ$$
Angle subtended by the diameter in a semicircle is 90$$^\circ$$
$$=$$> Â $$\angle$$ACB = 90$$^\circ$$
In cyclic quadrilateral ABCD, sum of opposite angles = 180$$^\circ$$
$$=$$> Â $$\angle$$BAD +Â $$\angle$$BCD =Â 180$$^\circ$$
$$=$$> Â $$\angle$$BAD +Â $$\angle$$ACB +Â $$\angle$$ACD =Â 180$$^\circ$$
$$=$$> Â $$\angle$$BAD +Â 90$$^\circ$$ + 50$$^\circ$$ = 180$$^\circ$$
$$=$$> Â $$\angle$$BAD + 140$$^\circ$$ = 180$$^\circ$$
$$=$$> Â $$\angle$$BAD =Â 40$$^\circ$$
Hence, the correct answer is Option B
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