Instructions

Use the table about the speed of a train over a 3-hour period. The time count does not begin from starting of train.

Question 106

During the three-hour period shown in the table, the speed of the train increased by

Solution

At t=0, speed was 40 kmph

At t=180, speed becomes 70 kmph

Therefore, increase in speed= $$\ \frac{\ 70-40}{40}.100=\ \frac{\ 30}{40}.100=75\%\ \ \ $$

Share on Whatsapp Share on Whatsapp

Create a FREE account and get:

All Quant Formulas and shortcuts PDF
170+ previous papers with solutions PDF
Top 5000+ MBA exam Solved Questions for Free

SNAP Quant Questions | SNAP Quantitative Ability

SNAP Inequalities Questions SNAP Logarithms, Surds and Indices Questions SNAP Linear Equations Questions SNAP Functions, Graphs and Statistics Questions SNAP Probability, Combinatorics Questions

SNAP DILR Questions | LRDI Questions For SNAP

SNAP Data Interpretation Questions SNAP Logical Reasoning Questions

SNAP Verbal Ability Questions | VARC Questions For SNAP

SNAP Grammar and Sentence Correction Questions SNAP Vocabulary Questions SNAP Para Summary Questions SNAP Para Jumbles Questions SNAP Reading Comprehension Questions

Also Read

SNAP Syllabus

SNAP Admit Card

SNAP Cutoffs

SNAP Eligibility Criteria

SNAP Exam Dates

SNAP Colleges List

SNAP Study Material

SNAP Registration

SNAP Result

SNAP Previous Year Papers

SNAP Crash Course

SNAP Mock Tests

Follow us on

Boost your Prep!

Download App