Instructions
Use the table about the speed of a train over a 3-hour period. The time count does not begin from starting of train.
Question 106
During the three-hour period shown in the table, the speed of the train increased by
Solution
At t=0, speed was 40 kmph
At t=180, speed becomes 70 kmph
Therefore, increase in speed= $$\ \frac{\ 70-40}{40}.100=\ \frac{\ 30}{40}.100=75\%\ \ \ $$
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