Instructions

Use the table about the speed of a train over a 3-hour period. The time count does not begin from starting of train.

Question 106

During the three-hour period shown in the table, the speed of the train increased by

Solution

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At t=0, speed was 40 kmph

At t=180, speed becomes 70 kmph

Therefore, increase in speed= $$\ \frac{\ 70-40}{40}.100=\ \frac{\ 30}{40}.100=75\%\ \ \ $$

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