Question 104

The radius of a hemispherical bowl is 6 cm. The capacity of the bowl is (Take $$\pi = \frac{22}{7}$$)

Solution

Given,

Radius of the hemispherical bowl = 6 cm

$$\therefore\ $$Capacity of the bowl = $$\frac{2}{3}\pi\ r^3=\frac{2}{3}\times\frac{22}{7}\times\ 6^3$$

$$=$$ 452.57 $$cm^3$$

Hence, the correct answer is Option B

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