L.C.M. of two numbers is 120 and their H.C.F. is 10. Which of the following can be the sum of those two numbers?
We assume that numbers are $$hr_1$$ and $$hr_2$$ (where h= H.C.F. of numbers and $$r_1$$Â and $$r_2$$ are prime factors)
So L.C.M. will be = $$hr_1r_2$$ = 120
or $$r_1r_2$$ = 12
So $$r_1$$ =4 and $$r_2$$ = 3 ; numbers will be 40 and 30, sum is 70
or $$r_1$$ = 12 and $$r_2$$ = 1 ; numbers will be 120 and 10, sum is 130
Hence only option D justifies.
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