Question 104

For a triangle ABC,D and E are two points on AB and AC such that AD = 1/4 AB, AE =1/4 AC. If BC = 12 cm, then DE is

Solution

Since, it is given that

=> $$\frac{AD}{AB} = \frac{AE}{AC} = \frac{1}{4}$$

=> $$\frac{AD}{AE} = \frac{AB}{AC}$$

=> $$\triangle$$ADE $$\sim$$ $$\triangle$$ABC

$$\therefore$$ DE = $$\frac{1}{4}$$ BC

= $$\frac{1}{4} * 12 = 3 cm$$

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