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Question 103
In 1 kg of a mixture of sand and iron, 20% is iron .How such sand should be added so that the proportion of iron becomes 10%
Solution
Total mixture of sand and iron = 1 kg
Quantity of iron = $$\frac{20}{100} \times 1 = 0.2$$ kg
Let $$x$$ kg of sand should be added, thus total iron in the mixture
=> $$0.2=\frac{10}{100} \times (x+1)$$
=> $$2=x+1$$
=> $$x=2-1=1$$ kg
=> Ans - (A)
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