Question 104
The denominator of a fraction is 2 more than thrice it’s numerator.If the numerator as well as denominator are increased by one,the fraction becomes ⅓ .what was that the original fraction?
Solution
Let the numerator = $$x$$
=> Denominator = $$(3x+2)$$
Fraction = $$\frac{x}{3x+2}$$
If the numerator as well as denominator are increased by one
=> $$\frac{x+1}{3x+2+1}=\frac{1}{3}$$
=> $$\frac{x+1}{3x+3}=\frac{1}{3}$$
=> $$3x+3=3x+3$$
It cannot be solved, thus $$x$$ can take any value and the fraction can be 2/8 , 3/11 , 4/14 ,....
=> Ans - (E)
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