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Question 103
A simple mechanism consists of 11 simple revolute joints and 9 links. What is the degree of freedom of the mechanism?
Solution
Number of links = $$N=9$$
Number of simple revolute joints lower pairs = $$L=11$$
Degree of freedom = $$f=3(N-1)-2L-H$$
=> $$f=3(9-1)-2\times11$$
=> $$f=24-22=2$$
=> Ans - (C)
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