Question 103

A simple mechanism consists of 11 simple revolute joints and 9 links. What is the degree of freedom of the mechanism?

Solution

Number of links = $$N=9$$

Number of simple revolute joints lower pairs = $$L=11$$

Degree of freedom = $$f=3(N-1)-2L-H$$

=> $$f=3(9-1)-2\times11$$

=> $$f=24-22=2$$

=> Ans - (C)


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