Question 102
Two taps A and B can fill a tank individually in 6 hours and 8 hours respectively and tap C can empty the same tank in 12 hours. If all the taps are kept open, how many hours would it take to fill the tank?
Solution
Let the volume of the tank = V
Let the efficiency of the tap A = V/A = V/6
And efficiency of the tap B = V/B = V/8
Efficiency of tap C to empty the tank = V/C = V/12
Let T be the total time taken by the system to fill the tank.
T*(V/6 + V/8 - V/ 12) = V
==> T = 24/5 = 4.8 hours.
So the correct option to choose is B - 4.8 hours.
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