The area of the iron sheet required to prepare a cone 24 cm high with base radius 7 cm is (Take $$\pi = \frac{22}{7}$$)
Surface area of cone= $$\frac{22}{7}\times r\times(r+L)$$
where L=slant height
L= $$\sqrt((r)^{2} + (h)^{2})$$
Here when r=7 and h=24,
L= $$\sqrt((7)^{2} + (24)^{2})$$ = $$\sqrt625$$ = 25cm
Area, A= $${\frac{22}{7}}\times7\times(7+25)$$
A= 704 $$(cm)^{2}$$
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