The angle of elevation of the Sun when the length of the shadow of a pole is equal to its height, is
Height of pole AB = Length of shadow BC = $$x$$
In $$\triangle$$ ABC,
=> $$tan(\angle$$Â $$ACB)=\frac{AB}{BC}$$
=> $$tan\theta=\frac{x}{x}$$
=> $$tan\theta=1$$
=> $$\theta=tan^{-1}(1)=45^\circ$$
=> Ans - (C)
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