If $$(\frac{3}{4})^{3}(\frac{4}{3})^{-7}=(\frac{3}{4})^{2x}$$ then x is
$$(\frac{4}{3})^{-7}$$ = $$(\frac{3}{4})^3$$
$$(\frac{3}{4})^{3}$$ x $$(\frac{3}{4})^3$$ = $$(\frac{3}{4})^{10}$$
It is given that
$$(\frac{3}{4})^{10}$$ = $$(\frac{3}{4})^{2x}$$
2x = 10
x = 5
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