Solution
The intercept form of the line = $$\ \frac{\ x}{a}+\ \frac{\ y}{b}\ =\ 1$$ where a is x-intercept and b is y-intercept.
3x + 4y - 12 = 0
3x + 4y = 12
$$\ \frac{3\ x}{12}+\ \frac{\ 4y}{12}\ =\ 1$$
$$\ \frac{\ x}{4}+\ \frac{\ y}{3}\ =\ 1$$
So the intercepts are 4 and 3.
B is the correct answer.
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