Solution
$$37800=2^3\cdot3^3\cdot5^2\cdot7$$
Hence, number of factors of 37800 = (3+1)*(3+1)*(2+1)*(1+1) = 96
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$$37800=2^3\cdot3^3\cdot5^2\cdot7$$
Hence, number of factors of 37800 = (3+1)*(3+1)*(2+1)*(1+1) = 96
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