The sum of $$11$$ consecutive natural numbers is $$121$$. The sum of the next three numbers is

Solution

Let the first of the $$11$$ numbers be $$n$$. Then $$11n+(1+2+\cdots+10)=121$$, so $$11n+55=121$$ and $$n=6$$. The next three numbers after $$6$$ through $$16$$ are $$17,18,19$$, whose sum is $$54$$.

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