Last 10 months to CAT 2025 🥳 Get upto 60% Off today on CAT 2025 Courses here
Edit MetaData
Let f(x) be a non-constant twice differentiable function defined on $$(-\infty, \infty)$$ such that f(x) = f(1 - x) and $$f'\left(\frac{1}{4}\right) = 0$$. Then,
$$f''(x)$$ vanishes at least twice on [0, 1]
$$f'\left(\frac{1}{2}\right) = 0$$
$$\int_{-\frac{1}{2}}^{\frac{1}{2}}f\left(x + \frac{1}{2}\right)\sin x dx = 0 $$
$$\int_{0}^{\frac{1}{2}}f(t)e^{\sin \pi t} dt = \int_{\frac{1}{2}}^{1}f(1 - t)e^{\sin \pi t} dt$$
Create a FREE account and get:
Login to your Cracku account.
Enter Valid Email
Follow us on
Incase of any issue contact support@cracku.in
Boost your Prep!
Day-wise Structured & Planned Preparation Guide
By proceeding you agree to create your account
Free CAT Schedule PDF will be sent to your email address soon !!!
Join cracku.in for Expert Guidance.