Given below are two statements :
Statement I : The number of pairs among [Ti$$^{4+}$$, V$$^{2+}$$], [V$$^{2+}$$, Mn$$^{2+}$$], [Mn$$^{2+}$$, Fe$$^{3+}$$] and [V$$^{2+}$$, Cr$$^{2+}$$] in which both ions are coloured is 3.
Statement II : The number of pairs among [La$$^{3+}$$, Yb$$^{2+}$$], [Lu$$^{3+}$$, Ce$$^{4+}$$] and [Ac$$^{3+}$$, Lr$$^{3+}$$] ions in which both are diamagnetic is 3.
In the light of the above statements, choose the correct from the options given below :

Statement I
Transition metal ions are typically coloured if they have partially filled $$d$$-orbitals ($$d^1$$ to $d^9$$ configuration), which allows for $$d\text{-}d$$ electronic transitions.

Ions with a $$d^0$$ or $$d^{10}$$ configuration are generally colourless.

There are exactly 3 pairs where both ions are coloured.

Statement I is CORRECT.

Statement II

An ion is diamagnetic if it has no unpaired electrons (i.e., all its orbitals are completely empty or completely filled).

1. $$[\text{La}^{3+}, \text{Yb}^{2+}]$$: Both are diamagnetic $$\rightarrow$$ True
2. $$[\text{Lu}^{3+}, \text{Ce}^{4+}]$$: Both are diamagnetic $$\rightarrow$$ True
3. $$[\text{Ac}^{3+}, \text{Lr}^{3+}]$$: Both are diamagnetic $$\rightarrow$$ True

There are exactly 3 pairs where both ions are diamagnetic.

• Statement II is CORRECT.

Option A: Both Statement I and Statement II are correct