Question 1

What is the least number that can be multiplied to 69120 to make it a perfect cube?

Solution

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Prime factorization of $$69120=2^9\times3^3\times5$$

For the number to be a perfect cube, all the exponents must be multiples of 3, thus the above number must be multiplied with $$5^2=25$$.

=> Ans - (C)

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