Question 1

Using the expression $$2d \sin \theta = \lambda$$, one calculates the values of d by measuring the corresponding angles $$\theta$$ in the range 0 to $$90^\circ$$. The wavelength $$\lambda$$ is exactly known and the error in $$\theta$$ is constant for all values of $$\theta$$. As $$\theta$$ increases from $$0^\circ$$,


Create a FREE account and get:

  • Free JEE Advanced Previous Papers PDF
  • Take JEE Advanced paper tests

cracku

Boost your Prep!

Download App