If the value of $$\sqrt{5}=2.236$$ then calculate the value of $$\sqrt{405}-\frac{1}{2}\sqrt{80}-\sqrt{125}$$
Given : $$\sqrt{5}=2.236$$
To find : $$\sqrt{405}-\frac{1}{2}\sqrt{80}-\sqrt{125}$$
= $$\sqrt{81\times5}-\frac{1}{2}\sqrt{16\times5}-\sqrt{25\times5}$$
= $$9\sqrt5-\frac{4}{2}\sqrt5-5\sqrt5$$
= $$2\sqrt5=2\times2.236=4.472$$
=> Ans - (B)
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