Question 1

Find the value of $${(216)^{\frac{2}{3}}+(36)^-{\frac{1}{2}}}$$

Solution

Expression = $${(216)^{\frac{2}{3}}+(36)^-{\frac{1}{2}}}$$

= $${(6^3)^{\frac{2}{3}}+(6^2)^-{\frac{1}{2}}}$$

= $$6^2+6^{-1}$$

= $$36+\frac{1}{6}$$

= $$\frac{(216+1)}{6}=\frac{217}{6}$$

=> Ans - (D)

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