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7 years, 1 month ago
5 years, 2 months ago
There are two cases
Case 1:- EKU & Miku are in car
If they are in car their seats are fixed, so no combination is required for them,
now we have 3 seats left, and 10 friends are there, so combinations will be
10C3= (10*9*8)/(3*2*1)= 120..............(1)
Case 1:- EKU & Miku are not in car
if they are not in car, we can not consider them for the combination
so, we have 5 seats and 10 friends to chose, and the combinations will be
10C5= (10*9*8*7*6)/(5*4*3*2*1)= 252 ...................(2)
so total combinatins are (1)+(2)= 120+252=372
Pradeep Khaire
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