What will be the minimum value of the sum of the squares of the roots of the equation x2- (m-3)x+m-8, when m is a positive integer After solving we arrive at the equation m2-8m+25, why can't I put m=1 to arrive at the lowest value

m cannot be equal to 1 as it will not provide the minimum value. f(1): 1- 8+25= 18. To arrive at the minimum value, you must use the formula to find the minimum value of any given quadratic equation -b/2a. The minimum of value of given equation or function will be at x = -b/2a = +8/2 = 4. f(4): 16-32+25=9

Thank you