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9 years, 1 month ago
9 years, 1 month ago
Lets assume P is going on the X axis to the east and Q is moving north on Y axis.
At time t = 0, P is at the origin (0,0) and Q is at (0, -50).
At time t = T, P is at (50T,0) and Q is at (0,-50 + 25T)
Distance between P and Q is $$ \sqrt {(50T)^{2} + (25T-50)^{2}}$$
= $$ \sqrt {3125T^{2} + 2500 - 2500T}$$
For that to be minimum, $$ 3125T^{2} + 2500 - 2500T $$ is minimum, ie derivative is 0
6250T - 2500 = 0 ie T = .4
Substituting T, we get distance = $$ 20 \sqrt (5)$$
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