TISSNET 2021

$$ 4^3, 6^3, 8^3$$

$$10^3,12^3,14^3$$

$$16^3,x^3,20^3$$

x should be 18

? = $$18^3$$ = 5832

Answer is option A.

$$P\left(1+\frac{r}{100}\right)^n-P\ =4347$$

$$\left(1+\frac{r}{100}\right)^n-1\ =\frac{4347}{30000}$$

$$\left(1+\frac{7}{100}\right)^n=\frac{11449}{10000}$$

n = 2

Answer is option A.

AA= {1, 2, 3, 4}; n(AA)= 4

BB= {1, 2, 3, 4}; n(BB)=4

So, AA=BB

364 days makes 52 weeks so we will take the remainder days in a year and add them.

For a period of 4 years the no. of days which we get = 2+1+1+1 =5

We have taken a period 4 years as a leap year occurs in every 4 years

Now, we have to make 5 days a multiple of 7 for which we have to multiply it with 7.

So, total years will be 4*7 = 28 years

Probability of getting 12(6,6) = $$\frac{1}{6}\cdot\frac{1}{6}=\frac{1}{36}$$

Gain or loss per throw = 40($$\frac{1}{36}$$) + (-2)($$\frac{35}{36}$$) = $$\frac{40}{36}-\frac{70}{36}=-\frac{30}{36}=-\frac{5}{6}$$

Loss of Rs $$\frac{5}{6}$$ for one throw.

Answer is option D.

In an hour, minute hand covers 60 units.

Units covered by hour hand = $$\ \frac{60}{12}$$ = 5 units.

Answer is option C.

The front door is facing east which means that the back door should be facing west.

Ranbir comes out of his from the back door which means he travels in the west direction for 100m and then turns right which means he is now travelling north. So finally Ranbir is in northwest direction from his office.

Rhombus is not a cyclic quadrilateral as the sum of opposite angles is not always 180 degrees.

Diagonals of a rhombus are not equal except in the case of a square.

A rhombus which is inscribed in a circle is always a square as it will be a cyclic quadrilateral for which the sum of opposite angles must be 180 degrees which is possible only when it is a square.

The opposite angles of a rhombus are equal.

$$1\frac{3}{4} \div \frac{1}{2}$$ can be written as $$\ \frac{\ \frac{7}{4}}{\frac{1}{2}}=\frac{7}{2}$$

option C - Half of $$1\frac{3}{4}=\frac{7}{4}$$ will be written as $$\ \frac{\ \frac{7}{4}}{2}=\frac{7}{8}$$

Therefore, the answer is option C.

If the distance travelled is the same during all the speeds then the average speed for the whole journey is the harmonic mean of the speed.