There are 8 speakers A,B,C,D,E,F,G and H in a conference. A,B and C always speak in alphabetical order. The probability that A,B and C are the first 3 speakers is a/b, where 'a' and 'b' are co-prime, find a+b.
This is one among the qstns I found in your video series for probability. I really didn'…

Question

There are 8 speakers A,B,C,D,E,F,G and H in a conference. A,B and C always speak in  alphabetical order. The probability that A,B and C are the first 3 speakers is a/b, where 'a' and 'b' are co-prime, find a+b.
This is one among the qstns I found in your video series for probability. I really didn't understand how the total no of outcomes became (8!/6), why can't we take A,B,C as one unit and consider the total no of outcomes to be 6! ?

pranav · Answer

Because it is a possibility that A,B,C are the 1st 3 speakers. A,B,C will speak in alphabetical order is affirmative.therefore total number of outcomes will be 8!/6

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