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8 years, 7 months ago
8 years, 7 months ago
Since there are 3 Os and 3 other letters, the selection of 4 letters can be done in three possible ways: one O, two Os and three Os.
One O: Number of ways of selecting 4 letters is 1.
Two Os: Number of ways of selecting 2 of the other 3 letters is $$^3C_2$$ = 3 ways
Three Os: Number of ways of selecting 1 of the other three letters is $$^3C_1$$ = 3 ways
So, total number of ways of selection = 3 + 3 + 1 = 7 ways
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