The number of non-real roots of the equation x^15+1=0 is ?

Question

Answer 1

x^15+1 = (x+1)(x^14 -x^13 +x^12 ---) = 0
The equation x+1=0 gives a real root
and equation (x^14 -x^13 +x^12 ---) = 0 gives 14 non-real roots.
Therefore, x^15+1 = 0 gives 1 real and 14 non-real roots.
Hope this helps
Thanks

Answer 2

x^15+1 = (x+1)(x^14 -x^13 +x^12 ---) = 0
The equation x+1=0 gives a real root
and equation (x^14 -x^13 +x^12 ---) = 0 gives 14 non-real roots.
Therefore, x^15+1 = 0 gives 1 real and 14 non-real roots.
Hope this helps
Thanks

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The number of non-real roots of the equation x^15+1=0 is ?