Edit MetaData
9 years, 1 month ago
9 years, 1 month ago
Since the decrease is uniform, the distance illuminated after 2 hours = 5 meters
Area initially illuminated = $$\pi * 9^2$$
Area illuminated after 2 hours = $$\pi * 5^2$$
Required area = $$81 \pi - 25 \pi = 56*22/7 = 176 m^2$$
Quick, Easy and Effective Revision
By proceeding you agree to create your account
Free CAT Formulae PDF will be sent to your email address soon !!!