2 years, 5 months ago
2 years, 4 months ago
Let batsmen played 'x' matches and avg is 48..so total runs =48x
Next match score = 103
So total of (48x+103) runs in (x+1) match
So new average = (48x+103) / (x+1)........... 1
And this value is a prime number less than 60..so only possible values r 53 and 59 as average won't be less than48.
So equating 1 with 53... x =10
Equating 1 with 59....x= 4
Sum of possible matches so = x+1= 11+5=16
2 years, 4 months ago
(48(x-1) + 103)/x = 53 or 59 gives x = 11 & 5 => sum = 16