Remainder 93! Mod 97 ?

Question

Answer 1

97 is prime number,so we can apply wilsons theorem here. 93!=(97-4)!, so According to Wilson's theorem,
(P-4)!/p=k where P is of 6k+1 form,
(P-4)!/p=p-k where p is of form 6k-1

Here 97=6(16)+1
So the remainder is 16.

Answer 2

97 is prime number,so we can apply wilsons theorem here. 93!=(97-4)!, so According to Wilson's theorem,
(P-4)!/p=k where P is of 6k+1 form,
(P-4)!/p=p-k where p is of form 6k-1

Here 97=6(16)+1
So the remainder is 16.

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Remainder 93! Mod 97 ?