Q 4 and f(0) and f(2) are of different signs. Which of the following is not a valid value for 'p'? f(x) = x4+2x2+p A. p = 2 B. p = 20 C. p = 16 D. p = 2

Question

Answer 1

Hi Swaroop,

Because they are of different signs, f(0)*f(2) < 0
Substituting the values and solving for 'p', we get -24 < p < 0
Looks like there's a mistake in the options. Please check.

Answer 2

Hi Swaroop,

Because they are of different signs, f(0)*f(2) < 0
Substituting the values and solving for 'p', we get -24 < p < 0
Looks like there's a mistake in the options. Please check.

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Q 4 and f(0) and f(2) are of different signs. Which of the following is not a valid value for 'p'? f(x) = x4+2x2+p A. p = ­ 2 B. p = ­20 C. p = ­16 D. p = 2

Q 4 and f(0) and f(2) are of different signs. Which of the following is not a valid value for 'p'? f(x) = x4+2x2+p A. p = 2 B. p = 20 C. p = 16 D. p = 2