Join WhatsApp Icon JEE WhatsApp Group

NTA JEE Main 10th April 2016 Online - Mathematics

For the following questions answer them individually

If the coefficients of $$x^{-2}$$ and $$x^{-4}$$, in the expansion of $$\left(x^{1/3} + \frac{1}{2x^{1/3}}\right)^{18}$$, $$(x \gt 0)$$, are $$m$$ and $$n$$ respectively, then $$\frac{m}{n}$$ is equal to

Let $$P = \{\theta : \sin\theta - \cos\theta = \sqrt{2}\cos\theta\}$$ and $$Q = \{\theta : \sin\theta + \cos\theta = \sqrt{2}\sin\theta\}$$, be two sets. Then

A ray of light is incident along a line which meets another line $$7x - y + 1 = 0$$ at the point $$(0, 1)$$. The ray is then reflected from this point along the line $$y + 2x = 1$$. Then the equation of the line of incidence of the ray of light is:

Equation of the tangent to the circle, at the point $$(1, -1)$$, whose center is the point of intersection of the straight lines $$x - y = 1$$ and $$2x + y = 3$$ is:

A hyperbola whose transverse axis is along the major axis of the conic $$\frac{x^2}{3} + \frac{y^2}{4} = 4$$ and has vertices at the foci of the conic. If the eccentricity of the hyperbola is $$\frac{3}{2}$$, then which of the following points does not lie on the hyperbola?

The contrapositive of the following statement, "If the side of a square doubles, then its area increases four times", is

The angle of elevation of the top of a vertical tower from a point A, due east of it is 45°. The angle of elevation of the top of the same tower from a point B, due south of A is 30°. If the distance between A and B is $$54\sqrt{2}$$ m, then the height of the tower (in meters), is:

Let $$A$$, be a $$3 \times 3$$ matrix, such that $$A^2 - 5A + 7I = O$$.
Statement - I: $$A^{-1} = \frac{1}{7}(5I - A)$$.
Statement - II: The polynomial $$A^3 - 2A^2 - 3A + I$$, can be reduced to $$5(A - 4I)$$. Then:

Let $$a, b \in R$$, $$(a \neq 0)$$. If the function $$f$$, defined as
$$f(x) = \begin{cases} \frac{2x^2}{a}, & 0 \leq x \lt 1 \\ a, & 1 \leq x \lt \sqrt{2} \\ \frac{2b^2 - 4b}{x^3}, & \sqrt{2} \leq x \lt 8 \end{cases}$$
is continuous in the interval $$[0, \infty)$$, then an ordered pair $$(a, b)$$ can be

Let C be a curve given by $$y(x) = 1 + \sqrt{4x - 3}$$, $$x > \frac{3}{4}$$. If $$P$$ is a point on C, such that the tangent at $$P$$ has slope $$\frac{2}{3}$$, then a point through which the normal at $$P$$ passes, is:

Let $$f(x) = \sin^4 x + \cos^4 x$$. Then, $$f$$ is an increasing function in the interval:

The integral $$\int \frac{dx}{(1+\sqrt{x})\sqrt{x - x^2}}$$ is equal to

For $$x \in R$$, $$x \neq 0$$, if $$y(x)$$ is a differentiable function such that $$x\int_1^x y(t)dt = (x+1)\int_1^x ty(t)dt$$, then $$y(x)$$ equals (where C is a constant)

The solution of the differential equation $$\frac{dy}{dx} + \frac{y}{2}\sec x = \frac{\tan x}{2y}$$, where $$0 \leq x < \frac{\pi}{2}$$ and $$y(0) = 1$$, is given by

$$ABC$$ is a triangle in a plane with vertices $$A(2, 3, 5)$$, $$B(-1, 3, 2)$$ and $$C(\lambda, 5, \mu)$$. If the median through $$A$$ is equally inclined to the coordinate axes, then the value of $$(\lambda^3 + \mu^3 + 5)$$ is

Let $$ABC$$ be a triangle whose circumcentre is at $$P$$. If the position vectors of $$A$$, $$B$$, $$C$$ and $$P$$ are $$\vec{a}$$, $$\vec{b}$$, $$\vec{c}$$ and $$\frac{\vec{a}+\vec{b}+\vec{c}}{4}$$ respectively, then the position vector of the orthocentre of this triangle, is: