JEE (Advanced) 2007 Paper-2

Instructions

If a continuous function f defined on the real line R, assumespositive and negative values in R then the equation f(x)=0 has a root in R. For example, if it is known that a continuous function f on R is positive at some point and its minimum value is negative then the equation f(x) = 0 has a root in R.
Consider $$f(x) = ke^x - x$$ for all real x where kis a real constant.

Question 61

The line y = x meets $$y = ke^x$$ for $$k \leq 0$$ at

Video Solution
Question 62

The positive value of k for which $$ke^x - x = 0$$ has only one root is

Video Solution
Question 63

For $$k > O$$, the set of all values of k for which $$ke^x - x = 0$$ has two distinct roots is

Video Solution
Instructions

For the following questions answer them individually

Question 64

Let $$f(x) = \frac{x^2 - 6x + 5}{x^2 - 5x + 6}$$.
Match the expressions/statements in Column I with expressions/statements in Column II and indicate your answer by darkening the appropriate bubbles in the $$4 \times 4$$ matrix given in the ORS.

Backspace
789
456
123
0.-
Clear All
Video Solution
Question 65

Let (x, y) be such that $$\sin^{-1}(ax) + \cos^{-1}(y) + \cos^{-1}(bxy) = \frac{\pi}{2}.$$
Match the statements in Column I with statements in Column II and indicate your answer by darkening the appropriate bubbles in the $$4 \times 4$$ matrix given in the ORS.

Backspace
789
456
123
0.-
Clear All
Video Solution
Question 66

Match the statements in Column I with the properties in Column II and indicate your answer by darkening the appropriate bubbles in the $$4 \times 4$$ matrix given in the ORS.

Backspace
789
456
123
0.-
Clear All
Video Solution
cracku

Boost your Prep!

Download App