How many ordered pairs of integers (x,y) satisfy the equn 1/x+3/y=1/29 where x>0 ?

8

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6 ordered pairs.
(x-29)(y-3*29)=3*29*29

total no of ordered pair solutions wil be equal to no of factors of 3*29*29 i.e 6 factors.

the equation reduces to y= 87x/(29-x) and the condition is 0

There will be 2 ordered pairs (28,1610),(26,928)