How can we calculate incircle of a right angled triangle?

Hi Saahil,

We can calculate the radius of the incircle of a right angled triangle given the sides of the triangle.
Let the side lengths of the right angled triangle be 6, 8 and 10. As, $$6^2+8^2 = 10^2$$, we know that these sides form a right angled triangle.
Inradius = $$\frac{area}{semi-perimeter}$$
Area = $$\frac{1}{2}*6*8$$ = 24
Semi-Perimeter = $$\frac{6+8+10}{2}$$ = 12
=> Inradius = $$\frac{24}{12}$$ = 2 units