hi could anyone let me know the formula for finding the number of ordered pairs of a given number. for eg the number of ordered pairs (a,b,c,d) where abcd=10800

Hi Vijay,
There's no direct formula. Firstly we need to factorise 10800 = 3^3*2^4*5^2.
Let x be the power of 2 in a, y be the power of 2 in b and z in c and w in d
x + y + z + w = 4 => Non-negative integral solutions = 7c3
Similarly for powers of 3 you will get 6C3 and for powers of 5, you will get 5c3.
So the required number of ordered pairs = 7c3*6c3*5c3.
Hope that helps.
Thanks