Given that a+b=3 , a^2+b^2=8 and; b should be greater than a. Then the value of b/a?

Hi We have a+b = 3 a^2+b^2 = 8 Now a^2 = 8-b^2 8-b^2 = 9+b^2-6b we get 2b^2-6b+1 =0 b = (6+rt28)/4 we get a = (6-rt28)/4 taking b/a we get (6+rt28/6-rt28)