Find the value of x for log 2 to the base x ×log 2 to the base x/16= log 2 to the base x/64

We have :
logx2 *logx/16 2=logx/64 2
Now we can write this as
1/log2x * 1/log2 x/16 = 1/log2 x/64
we get
log2 x/64 = log2X * log2 x/16
Now we know that log(a/b) = log(a) - log(b)
we get
log2x-log2 64 = log2 x( log2 x-log2 16)
log2X-6= log2X(log2X+4)
Let log2X= P
we get
p-6=p^2-4p
we get p^2-5p+6=0
p=3 and p=2
so log2x=3 and 2
we get x as 4 and 8

is X = 4??