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2 years, 9 months ago
2 years, 9 months ago
Hi
Let us say alloy has x kg of Zinc and y kg of Cu
Now from 1st case we can say : we add 3kg of pure Zn to alloy so we get total zinc as x+3 and cu as y now by condition we get (x+3)/y =9/1 we get 9y-x=3 ....(1)
Now 2Kg of 90% alloy means 1.8Kg Zinc and 0.2 Kg Cu
Now by condition (x+1.8)/x+y+2 =84/100 25x+45=21x+21y+42 or 21y-4x=3 ...(2)
equating 1 and 2 we get 21y-4x=9y-x
so we get 12y =3x or x =4y
Now percentage of Zinc = (x/x+y)*100
so we get 4/5*100 =80%
We have 9y-x=3
so 5y=3 or y=0.6 so x=2.4
Therefore weight of Zinc =2.4 Kg
2 years, 9 months ago
Sir, wouldnt it be (x+3)/y = 9/10 and we get 9y-10x = 30 instead ?
2 years, 9 months ago
Hi Rishi
Thank you for pointing out , by mistake I took 10 it would be 1 only as we are comparing with copper
so equation would be x+3/y =9 so we get 9y-x=3.
9/10 would be x+3/x+3+y , equating that would also be 9y-x=3.
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