Hi
This might be helpful for you. Please go through the following link https://cracku.in/banking/reasoning/banking-syllogisms/cheatsheet
Hope that helps.

is it 3/5525

that is (3*4C1/52C3)

Hi Omkar,

Numbers, Geometry, and VA are all very different topics.
For numbers, the varieties of questions asked are limited. The questions are essentially variations of similar question types. So practicing a lot of questions will get you acquainted with all the varieties and consequently improve your scores.   

For Geometry, first of all, you need to know all the theorems involved. Here, our thinking process is limited to our knowledge. We have some really good concept videos for the same. I will suggest you to start from there. 

For VA, you need to improve your reading skills. So, for starters, read a lot. Also, attempt a lot of mock tests and analyze them as to see which questions are you comfortable with. Come up with different test taking strategies and fine tune them as you go ahead.

Study Room has no video Siddiqui

Hi Siddiqui,

There are few concepts to keep in mind while attempting Para Jumbles.

1. Try to find Main Point of the paragraph. Every paragraph has an idea or a soul which should be identified. The sentences when constructed in the correct order reflect that idea. Try to find that idea and see what role a particular sentence will play in depicting the entire picture. Then arrange them accordingly to make paragraph coherent.

2. Try to see verbal connectives and logical connectives. These give hints regarding the sentences which follow and help in constucting a paragraph logically.

3. Try to see analogies as they should proceed with real life examples.

Hope this will help you. All the best.

Around 2000 students take the Mock CATs

Well you can try the following approach:
The question follows the sequence as
(100cb+101cb+102cb+103cb+104cb+105cb+106cb) gives remainder sequence as:
(2cb+3cb+4cb+5cb+6cb+0+1cb)=441/7= rem(0).
This cycle of 7 nos. will be repeated again till 999 after 106.
Thus,
=>106+7x=999
=>7x=893
Now dividing 893 by 7 will give us 4 as remainder.
This means that first 4 parts of the remainder sequence will be repeated and rest before them will yield 0 as remainder...
Thus,
Last 4 sequences i.e. 996cb+997cb+998cb+999cb will yeild remainders as:
2cb+3cb+4cb+5cb=224/7=rem(0).

You can check out our courses for banking here: https://cracku.in/banking/pricing

Hi
The binomial expansion formula is given by
(a+b)^n = nc0a^n + nc1*a^n-1*b + nc2*a^n-2*b^2 . .. . ... . .. 
Hope that helps.

Hi Shreyoshee,

                     We have a well-written blog on how to improve vocabulary.Please go through the link below to improve your vocabulary.

https://cracku.in/blog/improve-vocabulary-bank-exams/

Thanks,

Varun.