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6Â years ago
a man can row upstream at 7 k/h and downstream at 10 k/h find man's rate in still water and the rate of current
6Â years ago
If 'd' is the rate of speed in downstream and 'u' is the rate of speed in upstream
Rate in still water = 1/2(d+u)
Rate of current = 1/2(d-u)
Therefore, Rate in still water = 1/2(10+7) = 8.5 kmph
=> Rate of current = 1/2(10-7) = 1.5 kmph
6Â years ago
upstream(x-y)=7kmph
downstream(x+y)=10kmph
x+y+x-y=10-7
2x=3
x=1.5kmph
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