a lady says that her husband's age can be obtained by interchanging the digits of her own age which is 2 digit no. . he is older than her and sum of digit of their ages is 77 years . what is the units digit of her age . if difference between their ages is not more that 15 year

4 will be the answer. The ages will be 34 and 43.

Wherever it's showing &amp;it; and &gt; it means it's less than sign there. Idk what's wrong here. <br>The ans is 3<br>

LET WOMAN'S AGE BE XY AND MAN'S BE YX
YX&gt;XY (GIVEN, MAN'S OLDER THAN WOMAN)

XY+YX=77 (eq1, given)
YX-XY&lt;15(EQ2, given)
YX&gt;XY SO SUBTRACTING XY FROM YX

ADDING BOTH THE EQUATIONS
XY+YX=77
YX-XY&lt;15

2YX&lt;92( 72 PLUS ANYTHING LESS THAN 15 WILL GIVE OUT ANYTHING LESS THAN 92 AND ABOVE 77)

2YX&lt;92
YX&lt;46

YX CAN BE 45,44,43,42,41,40....

NOW CHECKING FOR VALUES THAT SATISFY THE GIVEN TWO EQUATIONS

IF YX=45 THEN XY=54( REVERSE OF IT)
YX&gt;XY
HERE XY COMES OUT TO BE GREATER( CASE REJECTED)

SIMILARLY, (44, 44)
HERE XY=YX
CONDITIONS VIOLATED

CHECK FOR YX=43, XY=34
43+34=77 (SATISFIED)
43-34&lt;15
9&lt;15
BOTH THE CONDITIONS TRUE

THUS THE VALUES ARE 43,34
THE UNITS DIGIT=3
YX(MAN) &gt;XY(WOMAN)
34= WOMAN'S AGE

.

the solution ???