a lady says that her husband's age can be obtained by interchanging the digits of her own age which is 2 digit no. . he is older than her and sum of digit of their ages is 77 years . what is the units digit of her age . if difference between their ages is not more that 15 year

4 will be the answer. The ages will be 34 and 43.

the solution ???

.

LET WOMAN'S AGE BE XY AND MAN'S BE YX YX>XY (GIVEN, MAN'S OLDER THAN WOMAN) XY+YX=77 (eq1, given) YX-XY<15(EQ2, given) YX>XY SO SUBTRACTING XY FROM YX ADDING BOTH THE EQUATIONS XY+YX=77 YX-XY<15 2YX<92( 72 PLUS ANYTHING LESS THAN 15 WILL GIVE OUT ANYTHING LESS THAN 92 AND ABOVE 77) 2YX<92 YX<46 YX CAN BE 45,44,43,42,41,40.... NOW CHECKING FOR VALUES THAT SATISFY THE GIVEN TWO EQUATIONS IF YX=45 THEN XY=54( REVERSE OF IT) YX>XY HERE XY COMES OUT TO BE GREATER( CASE REJECTED) SIMILARLY, (44, 44) HERE XY=YX CONDITIONS VIOLATED CHECK FOR YX=43, XY=34 43+34=77 (SATISFIED) 43-34<15 9<15 BOTH THE CONDITIONS TRUE THUS THE VALUES ARE 43,34 THE UNITS DIGIT=3 YX(MAN) >XY(WOMAN) 34= WOMAN'S AGE

Wherever it's showing &amp;it; and &gt; it means it's less than sign there. Idk what's wrong here. <br>The ans is 3<br>