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Instructions
In these questions, two equations numbered I and II are given. You have to solve both the equations and mark the appropriate answer. Give answer :
a:If x < y
b: If x > y
c: If x ≤ y
d: If x ≥ y
e: If relationship between x and y cannot be determined ,
Solution
I. $$6x^{2} - 5x + 1 = 0$$
=> $$6x^2 - 2x - 3x + 1 = 0$$
=> $$2x (3x - 1) - 1(3x - 1) = 0$$
=> $$(2x - 1) (3x - 1) = 0$$
=> $$x = \frac{1}{2} , \frac{1}{3}$$
II. $$12y^{2} - 23y + 10 = 0$$
=> $$12y^2 - 8y - 15y + 10 = 0$$
=> $$4y (3y - 2) - 3 (3y - 2) = 0$$
=> $$(4y - 3) (3y - 2) = 0$$
=> $$y = \frac{3}{4} , \frac{2}{3}$$
$$\therefore y > x$$
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