Question 97

What is the equilibrium expression for the reaction $$P_{4(s)} + 5O_{2(g)} \rightleftharpoons P_4O_{10(s)}$$?

Solution

Reaction:

$$P_4(s) + 5O_2(g) \rightleftharpoons P_4O_{10}(s)$$

Pure solids $$(s)$$ and pure liquids $$(l)$$ have constant activities, so their concentrations are omitted from the equilibrium expression (or treated as $$1$$).

Only gases $$(g)$$ and aqueous solutions $$(aq)$$ are included in the expression.

$$\left(K_c = \frac{\text{[Products]}}{\text{[Reactants]}}\right)$$:

$$K_c = \frac{1}{[O_2]^5}$$

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