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Question 97

Two pipes A and B can fill a tank in 10 hours and 15 hours respectively. If they are opened altemately for one hour each and if A is opened first, the time (in hours) required to fill the tank is

Solution

Let the total capacity of the tank be 30 liters

Hence, the capacity of the first pipe is 3 liters/hour and the capacity of the second pipe is 2 liters per hour.
Now, both the pipes are opened alternately for an hour each. Thus, in one round (or cycle) of 2 hours, net volume of tank filled = 3+2 = 5 liters
Hence, the tank will be completely filled in 30/5 = 6 rounds i.e. 12 hours

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