Solution
Expression : $$\sqrt{\frac{1}{sin^2A}+\frac{1}{cos^2A}}$$
= $$\sqrt{\frac{sin^2A+cos^2A}{sin^2A.cos^2A}}$$
= $$\sqrt{\frac{1}{sin^2A.cos^2A}}=\frac{1}{sinA.cosA}$$
= $$\frac{sin^2A+cos^2A}{sinA.cosA}$$
= $$\frac{sin^2A}{sinA.cosA}+\frac{cos^2A}{sinA.cosA}$$
= $$\frac{sinA}{cosA}+\frac{cosA}{sinA}=tanA+cotA$$
=> Ans - (B)
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