Given : $$cot\theta=\frac{24}{7}$$
=> $$tan\theta=\frac{7}{24}$$
Using, $$sec^2\theta-tan^2\theta=1$$
=> $$sec^2\theta=1+(\frac{7}{24})^2$$
=> $$sec^2\theta=1+\frac{49}{576}=\frac{625}{576}$$
=> $$sec\theta=\sqrt{\frac{625}{576}}=\frac{25}{24}$$
=> Ans - (B)
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